Integrand size = 19, antiderivative size = 24 \[ \int \frac {\sqrt {1+x^2}}{\sqrt {-1+x^4}} \, dx=-\frac {\sqrt {-1+x^4} \arcsin (x)}{\sqrt {1-x^4}} \]
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Time = 0.01 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.67, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {1166, 223, 212} \[ \int \frac {\sqrt {1+x^2}}{\sqrt {-1+x^4}} \, dx=\frac {\sqrt {x^2-1} \sqrt {x^2+1} \text {arctanh}\left (\frac {x}{\sqrt {x^2-1}}\right )}{\sqrt {x^4-1}} \]
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Rule 212
Rule 223
Rule 1166
Rubi steps \begin{align*} \text {integral}& = \frac {\left (\sqrt {-1+x^2} \sqrt {1+x^2}\right ) \int \frac {1}{\sqrt {-1+x^2}} \, dx}{\sqrt {-1+x^4}} \\ & = \frac {\left (\sqrt {-1+x^2} \sqrt {1+x^2}\right ) \text {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {x}{\sqrt {-1+x^2}}\right )}{\sqrt {-1+x^4}} \\ & = \frac {\sqrt {-1+x^2} \sqrt {1+x^2} \tanh ^{-1}\left (\frac {x}{\sqrt {-1+x^2}}\right )}{\sqrt {-1+x^4}} \\ \end{align*}
Time = 0.50 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.42 \[ \int \frac {\sqrt {1+x^2}}{\sqrt {-1+x^4}} \, dx=-\log \left (1+x^2\right )+\log \left (x+x^3+\sqrt {1+x^2} \sqrt {-1+x^4}\right ) \]
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Time = 0.23 (sec) , antiderivative size = 33, normalized size of antiderivative = 1.38
method | result | size |
default | \(\frac {\sqrt {x^{4}-1}\, \ln \left (x +\sqrt {x^{2}-1}\right )}{\sqrt {x^{2}+1}\, \sqrt {x^{2}-1}}\) | \(33\) |
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Leaf count of result is larger than twice the leaf count of optimal. 65 vs. \(2 (20) = 40\).
Time = 0.24 (sec) , antiderivative size = 65, normalized size of antiderivative = 2.71 \[ \int \frac {\sqrt {1+x^2}}{\sqrt {-1+x^4}} \, dx=\frac {1}{2} \, \log \left (\frac {x^{3} + \sqrt {x^{4} - 1} \sqrt {x^{2} + 1} + x}{x^{3} + x}\right ) - \frac {1}{2} \, \log \left (-\frac {x^{3} - \sqrt {x^{4} - 1} \sqrt {x^{2} + 1} + x}{x^{3} + x}\right ) \]
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\[ \int \frac {\sqrt {1+x^2}}{\sqrt {-1+x^4}} \, dx=\int \frac {\sqrt {x^{2} + 1}}{\sqrt {\left (x - 1\right ) \left (x + 1\right ) \left (x^{2} + 1\right )}}\, dx \]
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\[ \int \frac {\sqrt {1+x^2}}{\sqrt {-1+x^4}} \, dx=\int { \frac {\sqrt {x^{2} + 1}}{\sqrt {x^{4} - 1}} \,d x } \]
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\[ \int \frac {\sqrt {1+x^2}}{\sqrt {-1+x^4}} \, dx=\int { \frac {\sqrt {x^{2} + 1}}{\sqrt {x^{4} - 1}} \,d x } \]
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Timed out. \[ \int \frac {\sqrt {1+x^2}}{\sqrt {-1+x^4}} \, dx=\int \frac {\sqrt {x^2+1}}{\sqrt {x^4-1}} \,d x \]
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